Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan theta}{1+tan ^{2}theta}
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How do you prove sin(90°-a) = cos(a)?
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Prove that : tantheta+tantheta+tan(90^(@)-theta)=sectheta*sec(90^(@)-t
SOLVED: 'Please give all answers correctly Choose the correct alternative answer for following multiple choice questions. L. () Which of the following statements is true ? (A) sin 0 = cos (90
सिद्ध कीजिए कि sin(90^(@)-theta)cos(90^(@)-theta)=(tan theta)/(1+cot^(2 )(90^(@)-theta)), 10
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सिद्ध कीजिए कि sin (90 - theta) cos (90 - theta) = (tan theta)/(1 + tan^2 theta), 10
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Prove that dfrac{sin (180^{o}+theta)cos(90^{o}+theta)tan (270^{o}-theta)cot (360^{o}-theta)}{sin(360^{o}-theta)cos (360^{o}+theta)csc(-theta)sin (270^{o}+theta)}=1
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