Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin^2 θ - Sarthaks

Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin2 θ

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Telugu] (sin(90-theta)sintheta)/(tantheta)-1 = ………………

Maths] If 1 + sin^2θ = 3sinθ cosθ , then prove that tanθ = 1 or 1/2

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sin(90-theta)* cos(90-theta) = tan theta/ 1+ tan^2 theta

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