Find the value of underroot 6+underroot 6 + underroot 6+
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If dfrac { 5+sqrt { 6 } }{ 5-sqrt { 6 } } =a+bsqrt { 6 } , then the value of 'a' and 'b'.
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Find value of x , If x=sqrt { 6+sqrt { 6 } +sqrt { 6 } +.infty } where x is a natural number.
The value of sqrt(6+sqrt(6+sqrt(6+))) .is (a) 4 (b) 3 (c)
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represent root 6 on number line by Pythagoras method
sqrt(6+sqrt(6+sqrt(6+…oo))) is equal to .
The Value of root 6 + root 6 + root 6 ----- is Conceptual Solution